Integrand size = 17, antiderivative size = 568 \[ \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx=\frac {2^{-3-n} e^{i (3 a-c n)+i (3 b-d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n,\frac {1}{2} \left (2+\frac {3 b}{d}-n\right ),-e^{2 i (c+d x)}\right )}{3 b-d n}-\frac {3\ 2^{-3-n} e^{i (a-c n)+i (b-d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (-n,\frac {b-d n}{2 d},\frac {1}{2} \left (2+\frac {b}{d}-n\right ),-e^{2 i (c+d x)}\right )}{b-d n}-\frac {3\ 2^{-3-n} e^{-i (a+c n)-i (b+d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (-n,-\frac {b+d n}{2 d},1-\frac {b+d n}{2 d},-e^{2 i (c+d x)}\right )}{b+d n}+\frac {2^{-3-n} e^{-i (3 a+c n)-i (3 b+d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (-n,-\frac {3 b+d n}{2 d},\frac {1}{2} \left (2-\frac {3 b}{d}-n\right ),-e^{2 i (c+d x)}\right )}{3 b+d n} \]
2^(-3-n)*exp(I*(-c*n+3*a)+I*(-d*n+3*b)*x+I*n*(d*x+c))*(exp(-I*(d*x+c))+exp (I*(d*x+c)))^n*hypergeom([-n, 3/2*b/d-1/2*n],[1+3/2*b/d-1/2*n],-exp(2*I*(d *x+c)))/((1+exp(2*I*c+2*I*d*x))^n)/(-d*n+3*b)-3*2^(-3-n)*exp(I*(-c*n+a)+I* (-d*n+b)*x+I*n*(d*x+c))*(exp(-I*(d*x+c))+exp(I*(d*x+c)))^n*hypergeom([-n, 1/2*(-d*n+b)/d],[1+1/2*b/d-1/2*n],-exp(2*I*(d*x+c)))/((1+exp(2*I*c+2*I*d*x ))^n)/(-d*n+b)-3*2^(-3-n)*exp(-I*(c*n+a)-I*(d*n+b)*x+I*n*(d*x+c))*(exp(-I* (d*x+c))+exp(I*(d*x+c)))^n*hypergeom([-n, 1/2*(-d*n-b)/d],[1+1/2*(-d*n-b)/ d],-exp(2*I*(d*x+c)))/((1+exp(2*I*c+2*I*d*x))^n)/(d*n+b)+2^(-3-n)*exp(-I*( c*n+3*a)-I*(d*n+3*b)*x+I*n*(d*x+c))*(exp(-I*(d*x+c))+exp(I*(d*x+c)))^n*hyp ergeom([-n, 1/2*(-d*n-3*b)/d],[1-3/2*b/d-1/2*n],-exp(2*I*(d*x+c)))/((1+exp (2*I*c+2*I*d*x))^n)/(d*n+3*b)
Time = 2.60 (sec) , antiderivative size = 329, normalized size of antiderivative = 0.58 \[ \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx=2^{-3-n} e^{i (-3 a+c+d (1+n) x)} \left (e^{-i (c+d x)} \left (1+e^{2 i (c+d x)}\right )\right )^{1+n} \left (\frac {e^{-i (3 b+d n) x} \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2} \left (2-\frac {3 b}{d}+n\right ),1-\frac {3 b}{2 d}-\frac {n}{2},-e^{2 i (c+d x)}\right )}{3 b+d n}-\frac {3 e^{2 i a-i (b+d n) x} \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2} \left (2-\frac {b}{d}+n\right ),-\frac {b+d (-2+n)}{2 d},-e^{2 i (c+d x)}\right )}{b+d n}+e^{i (4 a+b x-d n x)} \left (\frac {e^{2 i (a+b x)} \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2} \left (2+\frac {3 b}{d}+n\right ),1+\frac {3 b}{2 d}-\frac {n}{2},-e^{2 i (c+d x)}\right )}{3 b-d n}-\frac {3 \operatorname {Hypergeometric2F1}\left (1,\frac {b+d (2+n)}{2 d},\frac {1}{2} \left (2+\frac {b}{d}-n\right ),-e^{2 i (c+d x)}\right )}{b-d n}\right )\right ) \]
2^(-3 - n)*E^(I*(-3*a + c + d*(1 + n)*x))*((1 + E^((2*I)*(c + d*x)))/E^(I* (c + d*x)))^(1 + n)*(Hypergeometric2F1[1, (2 - (3*b)/d + n)/2, 1 - (3*b)/( 2*d) - n/2, -E^((2*I)*(c + d*x))]/(E^(I*(3*b + d*n)*x)*(3*b + d*n)) - (3*E ^((2*I)*a - I*(b + d*n)*x)*Hypergeometric2F1[1, (2 - b/d + n)/2, -1/2*(b + d*(-2 + n))/d, -E^((2*I)*(c + d*x))])/(b + d*n) + E^(I*(4*a + b*x - d*n*x ))*((E^((2*I)*(a + b*x))*Hypergeometric2F1[1, (2 + (3*b)/d + n)/2, 1 + (3* b)/(2*d) - n/2, -E^((2*I)*(c + d*x))])/(3*b - d*n) - (3*Hypergeometric2F1[ 1, (b + d*(2 + n))/(2*d), (2 + b/d - n)/2, -E^((2*I)*(c + d*x))])/(b - d*n )))
Time = 1.37 (sec) , antiderivative size = 548, normalized size of antiderivative = 0.96, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {5066, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sin ^3(a+b x) \cos ^n(c+d x) \, dx\) |
\(\Big \downarrow \) 5066 |
\(\displaystyle 2^{-n-3} \int \left (3 i e^{-i a-i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-3 i e^{i a+i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-i e^{-3 i a-3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n+i e^{3 i a+3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle 2^{-n-3} \left (\frac {\left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \operatorname {Hypergeometric2F1}\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n,\frac {1}{2} \left (\frac {3 b}{d}-n+2\right ),-e^{2 i (c+d x)}\right ) \exp (i (3 a-c n)+i x (3 b-d n)+i n (c+d x))}{3 b-d n}-\frac {3 \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \operatorname {Hypergeometric2F1}\left (-n,\frac {b-d n}{2 d},\frac {1}{2} \left (\frac {b}{d}-n+2\right ),-e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac {3 \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \operatorname {Hypergeometric2F1}\left (-n,-\frac {b+d n}{2 d},1-\frac {b+d n}{2 d},-e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n}+\frac {\left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \operatorname {Hypergeometric2F1}\left (-n,-\frac {3 b+d n}{2 d},\frac {1}{2} \left (-\frac {3 b}{d}-n+2\right ),-e^{2 i (c+d x)}\right ) \exp (-i (3 a+c n)-i x (3 b+d n)+i n (c+d x))}{3 b+d n}\right )\) |
2^(-3 - n)*((E^(I*(3*a - c*n) + I*(3*b - d*n)*x + I*n*(c + d*x))*(E^((-I)* (c + d*x)) + E^(I*(c + d*x)))^n*Hypergeometric2F1[((3*b)/d - n)/2, -n, (2 + (3*b)/d - n)/2, -E^((2*I)*(c + d*x))])/((1 + E^((2*I)*c + (2*I)*d*x))^n* (3*b - d*n)) - (3*E^(I*(a - c*n) + I*(b - d*n)*x + I*n*(c + d*x))*(E^((-I) *(c + d*x)) + E^(I*(c + d*x)))^n*Hypergeometric2F1[-n, (b - d*n)/(2*d), (2 + b/d - n)/2, -E^((2*I)*(c + d*x))])/((1 + E^((2*I)*c + (2*I)*d*x))^n*(b - d*n)) - (3*E^((-I)*(a + c*n) - I*(b + d*n)*x + I*n*(c + d*x))*(E^((-I)*( c + d*x)) + E^(I*(c + d*x)))^n*Hypergeometric2F1[-n, -1/2*(b + d*n)/d, 1 - (b + d*n)/(2*d), -E^((2*I)*(c + d*x))])/((1 + E^((2*I)*c + (2*I)*d*x))^n* (b + d*n)) + (E^((-I)*(3*a + c*n) - I*(3*b + d*n)*x + I*n*(c + d*x))*(E^(( -I)*(c + d*x)) + E^(I*(c + d*x)))^n*Hypergeometric2F1[-n, -1/2*(3*b + d*n) /d, (2 - (3*b)/d - n)/2, -E^((2*I)*(c + d*x))])/((1 + E^((2*I)*c + (2*I)*d *x))^n*(3*b + d*n)))
3.3.23.3.1 Defintions of rubi rules used
Int[Cos[(c_.) + (d_.)*(x_)]^(q_.)*Sin[(a_.) + (b_.)*(x_)]^(p_.), x_Symbol] :> Simp[1/2^(p + q) Int[ExpandIntegrand[(E^((-I)*(c + d*x)) + E^(I*(c + d *x)))^q, (I/E^(I*(a + b*x)) - I*E^(I*(a + b*x)))^p, x], x], x] /; FreeQ[{a, b, c, d, q}, x] && IGtQ[p, 0] && !IntegerQ[q]
\[\int \cos \left (d x +c \right )^{n} \sin \left (x b +a \right )^{3}d x\]
\[ \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx=\int { \cos \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3} \,d x } \]
Timed out. \[ \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx=\text {Timed out} \]
\[ \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx=\int { \cos \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3} \,d x } \]
\[ \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx=\int { \cos \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3} \,d x } \]
Timed out. \[ \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx=\int {\cos \left (c+d\,x\right )}^n\,{\sin \left (a+b\,x\right )}^3 \,d x \]